
#AREA OF A RECTANGLE PLUS#
This tells us that, for any pair of coordinates, π₯ one, π¦ one and π₯ two, π¦ two, the distance can be found by the square root of π₯ two minus π₯ one all squared plus π¦ two minus π¦ one all squared. This is the diagonal of the rectangle going from π΄ to πΆ.Δͺs we know the coordinate values for vertices π΄ and πΆ, we can recall the formula for the distance between two points. Now that weβve found the coordinate values of all four vertices, letβs see if we can find the length of this line segment π΄πΆ. So the coordinate of π΅ must be zero, five. Therefore, the π₯-coordinate will be zero, and the π¦-value will be the same as that of π΅. We can alternatively think of this that the line segment ππ΄ must be 12 units long.

We can see that point π΄ sits on the π₯-axis, so the π¦-value will be zero. We know that π΅ lies at 12 on the π₯-axis, and therefore π΄ must also lie at 12 on the π₯-axis. So letβs look at this vertex π΄ in relation to π΅. And we can be sure that ππΆ and π΄π΅ will be vertical lines. So weβll have right angles at angles π, π΄, π΅, and πΆ. We must remember that the definition of a rectangle is that all interior angles are 90 degrees. And so the line π΅πΆ must also be a horizontal line. We know that the line ππ΄ lies on the π₯-axis, which is a horizontal line. This other important piece of information that π΅ is at 12, five will help us work out the coordinates of vertices π΄ and πΆ. So in order to answer this question, weβll need to look a little bit more closely at the vertices.Δ―irstly, this vertex of π must be the coordinate or ordered pair of zero, zero. We might notice that weβre not given any lengths in this diagram.


In this question, we can see this rectangle π΄π΅πΆπ and we need to find a length and the area. Given that π΄π΅πΆπ is a rectangle, find the length of line segment π΄πΆ and the area of the rectangle.
